A solution of 10% sulfuric acid and one of 25% sulfuric acid are to be used to make 500 ml of 20% sulfuric acid. How many ml of each solution needs to be used in the mixture? (round answers to the nearest ml)

Step-by-step explanation:If x is the volume of the 10% sulfuric acid, and y is the volume of 25% sulfuric acid, then:x + y = 5000.10 x + 0.25 y = 0.20 (500)Solve the system of equations with substitution or elimination.  Using substitution:y = 500 − x0.10 x + 0.25 (500 − x) = 0.20 (500)0.10 x + 125 − 0.25 x = 10025 = 0.15 xx = 167 mLy = 333 mLYou need 167 mL of 10% sulfuric acid and 333 mL of 25% sulfuric acid.