MATH SOLVE

5 months ago

Q:
# If a rectangle's length is 2t+1and the width is t-3 write an expression for the perimeter and an expression for the area.

Accepted Solution

A:

Answer:Perimeter = 6t - 4Area = 2t² - 7t - 3Step-by-step explanation:Given length = 2t + 1 Width = t - 3 So perimeter = 2t +1 + t - 3 + 2t + 1 + t - 3 = 2t + t + 2t + t + 1 - 3 + 1 - 3 = 6t - 4 Area = (2t + 1)(t - 7) = 2t² - 6t + t - 3 = 2t² - 7t - 3Sorry if im wrong but i think thats the answer