MATH SOLVE

2 months ago

Q:
# I would appreciate the help please!!The graph of y = x2 β7x +12 is a parabola with x-intercepts at: {-3 and -4, or 3 and 4} and a vertex that is the: {lowest or highest} point on the curve. Thanks in advance!

Accepted Solution

A:

xΒ² - 7x +12 = 0

(x-3)(x-4)=0

x= 3 or 4

since the leading coefficient is positive the parabola opens up and the vertex is a minimum

(x-3)(x-4)=0

x= 3 or 4

since the leading coefficient is positive the parabola opens up and the vertex is a minimum