I would appreciate the help please!!The graph of y = x2 β7x +12 is a parabola with x-intercepts at: {-3 and -4, or 3 and 4} and a vertex that is the: {lowest or highest} point on the curve. Thanks in advance!
Accepted Solution
A:
xΒ² - 7x +12 = 0 (x-3)(x-4)=0 x= 3 or 4 since the leading coefficient is positive the parabola opens up and the vertex is a minimum