What is the slope of a line passing through (3, 8) and (5, 5)?
Accepted Solution
A:
Answer:Step-by-step explanation:bYour input is P=(3,8) and Q=(5,5).
The slope of the line passing through the two points P=(x1,y1) and Q=(x2,y2) is given by m=y2βy1x2βx1.
We have that x1=3, y1=8, x2=5, y2=5.
Plug the given values into the formula for the slope: m=(5)β(8)(5)β(3)=β32=β32.
Now, the y-intercept is b=y1βmβ x1 (or b=y2βmβ x2, the result is the same).
b=8β(β32)β (3)=252.
Finally, the equation of the line can be written in the form y=mx+b.
y=β32x+252.
Answer:
The slope of the line is m=β32=β1.5.
The y-intercept is (0,252)=(0,12.5).
The equation of the line in the slope-intercept form is y=β32x+252=β1.5x+12.5