Determine if x + 3 is a factor of -3[tex]x^{3}[/tex]+6[tex]x^{2}[/tex]+6x+9. How do you know? no, because the remainder is 126yes, because the remainder is 126no, because the remainder is –108yes, because the remainder is –108
Accepted Solution
A:
Answer:Option Cno, because the remainder is 126Step-by-step explanation:Given the polynomial equation in the question -3x^{3}+6x^{2}+6x+9factor = x + 3 (divisor)long division -3x² + 15x - 39 Quotient -------------------------------- x + 3| -3x³ + 6x² + 6x + 9 Dividend | -3x³ - 9x² ---------------------- 15x² + 6x + 9 15x² + 45x -------------------- -39x + 9 -39x - 117 ------------- 126 ReminderSince reminder is not zero so (x + 3) is not factor of -3x³ + 6x² + 6x + 9.(x-3) is the factor of -3x³ + 6x² + 6x + 9.